# Practice Question & Solution | Set 1

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1. What percent of a day in 6 hours?
1.25%
2.52%
3.50%
4.5%
2. Two-fifth of one-third of three seventh of a number is 15.What is 40% of that number?
1.501
2.105
3.525
4.150
3. The population of of a town is 176000.If it increase at the rate of 5% per annum,what will be it’s population 2 years hence?
1.194000
2.194040
3.190440
4.194104
4. The length and breath of a rectangle are increased by 20% and 30%.The area of the resulting rectangle exceeds the area of the original rectangle?
1.50%
2.65%
3.56%
4.156%
5. Water tax is is increased by 20% but its consumption is decreased by 20%.Then increase or decrease in the expenditure of the money is
1.40%
2.4%
3.96%
4.None of the above.
6. Sugar contain 5% water .What quantity of pure Sugar should be added to 10 litres of water to reduce this to 2%.
1.5lit
2.6lit
3.10lit
4.15lit
7. In an election between 2 candidates,Candidate who gets 40% of the total vote defeated by 15000.The no of votes polled by winner
1.10000
2.45000
3.30000
4.6000
8. The price of a fan is decreased by 20%.as a result of wh ich the sale increased by 40%.What will be the effect on the total revenue of the shop?
1.12%
2.10%
3.20%
4.30%
9. Raj save 10%,after 2 years when his income is increased by 10%,he could save the same money then how much his expenditure increased?
1.10%
2.20%
3.5%
4.15%
10. If x% of y is equal to z then what percentage of z is x?
1.y2  /100
2.x  2/100
3.1002/y
4.1002/x

#### Solution

1. Ans: A) 25%
Solution:(6/24)×100=25%
2. Ans : B) 105
Solution:(2/5)(1/3)(3/7)×x=15.
X=(15×(7/3)×(5/2)×3)=525/2.
40% of x=(40/100)(525/2)=>105.
3. Ans: B) 194040
Solution:176000×(105/100)(105/100)=88×105×21=194040.
4. Ans: C)56%
Solution:(120/100) ×(130/100) ×100=156.
156-100=56.
5. Ans: B) 4%
Solution:((20×20)/100)=4.
6. Ans: D) 15lit
Solution:0.5/(x+10)=2/100.
2x=30
X=15.
7. Ans: B) 45000
Solution:40%-looser,60%-winner, defeated 15000=20%
Winner=60%=15000×3=45000.
8. Ans: A) 12%
Solution:Original revenue=100×100=10000.
After 20% decrease=80×140=11200.
Hence [(11200-10000)/10000] ×100=[1200/10000] ×100
=12%.
9. Ans: A) 10%
Solution:Let income=100,saving=10 and expenditure=90.
New income=110,saving=11 and e=99.
E increased %=[(99-90)/90] ×100=(9/90)×100=10%.
10. Ans: C) 1002/y
Solution:(x/100)y=z;
(x/z)=(100/y).
(x/z) ×100=100×(100/y)=>1002/y.